2(z+1)^2-(z-3)=22z-4

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Solution for 2(z+1)^2-(z-3)=22z-4 equation: 



2(z+1)^2-(z-3)=22z-4

We move all terms to the left:

2(z+1)^2-(z-3)-(22z-4)=0

We get rid of parentheses

2(z+1)^2-z-22z+3+4=0

We add all the numbers together, and all the variables

-23z+2(z+1)^2+7=0

We move all terms containing z to the left, all other terms to the right

-23z+2(z+1)^2=-7

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